X^2+17x-1=0

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Solution for X^2+17x-1=0 equation: 



X^2+17X-1=0

a = 1; b = 17; c = -1;
Δ = b2-4ac
Δ = 172-4·1·(-1)
Δ = 293
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{293}}{2*1}=\frac{-17-\sqrt{293}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{293}}{2*1}=\frac{-17+\sqrt{293}}{2}
$

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